Hi Santosh, One way would be
> sapply(d, "[", 1) [1] "20110405" "20110405" "20110405" "20110405" "20110405" "20110405" HTH, Jorge On Thu, Apr 7, 2011 at 2:14 AM, santosh <> wrote: > Hello Group, > > Is there a simpler way to get data out of a list object? (like in data > frame without using the apply functions) > > I have the following dataset > > > dput(d) > list(c("20110405", "092102"), c("20110405", "092538"), c("20110405", > "093458"), c("20110405", "101124"), c("20110405", "102041"), > c("20110405", "103659")) > > I extracted my data like this: > > getDate <- function(x)(unlist(x[[1]])) > > unlist(lapply(d, getDate)) > [1] "20110405" "20110405" "20110405" "20110405" "20110405" "20110405" > > Isn't there an easier way to do this? > > Thanks, > Santosh > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.