I think it was suggested that you save your output to a 'list' and
then you will have it in a format that can accept variable numbers of
items in each element and it is also in a form that you can easily
process it to create whatever other output you might need.
On Fri, Mar 18, 2011 at 7:24 AM, Ram H. Sharma <sharma.ra...@gmail.com> wrote:
> Hi Dennis and R-users
>
> Thank you for more help. I am pretty close, but challenge still remain is
> forcing the output with different length to output dataframe.
>
>> x <- data.frame(apply(datafr1, 2, fout))
> Error in data.frame(var1 = c(-0.70777998321315, 0.418602152926712,
> 2.08356737154810, :
> arguments imply differing number of rows: 28, 12, 20, 19
>
> As I need to work with >2000 variables, my intension here is to save this
> output to such way that it would be further manipulated. Topline is to save
> in dataframe that have extreme values for the variable concerned and
> bottomline is automate to save the output printed in the screen to a
> textfile.
>
> Thank you for help once again.
>
> Ram
>
>
> On Fri, Mar 18, 2011 at 3:16 AM, Dennis Murphy <djmu...@gmail.com> wrote:
>
>> Hi:
>>
>> Is this what you're after?
>>
>> fout <- function(x) {
>> lim <- median(x) + c(-2, 2) * mad(x)
>> x[x < lim[1] | x > lim[2]]
>> }
>> > apply(datafr1, 2, fout)
>> $var1
>> [1] 17.5462078 18.4548214 0.7083442 1.9207578 -1.2296787 17.4948240
>> [7] 19.5702558 1.6181150 20.9791652 -1.3542099 1.8215087 -1.0296303
>> [13] 20.5237930 17.5366497 18.5657566 0.9335419 19.7519983 17.8607968
>> [19] 19.1307524 19.6145711 21.8037136 19.1532175 -2.6688409 19.6949309
>> [25] 1.9712347
>>
>> $var2
>> [1] 37.3822087 35.6490641 35.6000785 38.5981086 -1.6504275
>> 37.1419290
>> [7] 37.7605230 40.3508689 0.6639900 2.4695841 38.8209491
>> 39.9087921
>> [13] 38.9907585 35.8279437 2.7870799 37.0941113 0.6308583
>> 36.4556638
>> [19] -10.2384849 2.8480199 -7.7680457 35.7076539 -0.5467739
>> 3.4702765
>> [25] 40.4818580 3.2864273 1.4917174
>>
>> $var3
>> [1] 74.252563 68.396391 68.845461 -5.006545 66.083402 76.036577
>> [7] 75.112586 -6.374241 63.883549 64.041216 -19.764360 -15.051017
>> [13] -9.782767 64.696013 70.970648 -4.562031 -22.135003 70.549310
>> [19] 69.495915 -4.095587 86.612375 87.029526 70.072126 -6.421695
>> [25] 65.737536
>>
>> $var4
>> [1] 81.476483 87.098767 -10.451616 91.927329 86.588952 85.080950
>> [7] 84.958645 -9.456368 86.270876 -22.936779 83.314032
>>
>> Double checks:
>> > apply(datafr1, 2, function(x) median(x) + c(-2, 2) * mad(x))
>> var1 var2 var3 var4
>> [1,] 2.12167 3.779415 -3.736066 -3.471752
>> [2,] 17.37176 34.929800 62.969733 80.224799
>> > apply(datafr1, 2, range)
>> var1 var2 var3 var4
>> [1,] -2.668841 -10.23848 -22.13500 -22.93678
>> [2,] 21.803714 40.48186 87.02953 91.92733
>>
>> Assuming you wanted to do this columnwise (by variable), it appears to be
>> doing the right thing.
>>
>> HTH,
>> Dennis
>>
>>
>> On Thu, Mar 17, 2011 at 7:04 PM, Ram H. Sharma <sharma.ra...@gmail.com>wrote:
>>
>>> Dear R community members
>>>
>>> I have been struggling on this simple question, but never get appropriate
>>> solution. So please help.
>>>
>>> # my data, though I have a large number of variables
>>> var1 <- rnorm(500, 10,4)
>>> var2 <- rnorm(500, 20, 8)
>>> var3 <- rnorm(500, 30, 18)
>>> var4 <- rnorm(500, 40, 20)
>>> datafr1 <- data.frame(var1, var2, var3, var4)
>>>
>>> # my unsuccessful codes
>>> nvar <- ncol(datafr1)
>>> for (i in 1:nvar) {
>>> out1 <- NULL
>>> out2 <- NULL
>>> medianx <- median(getdata[,i], na.rm = TRUE)
>>> show(madx <- mad(getdata[,i], na.rm = TRUE))
>>> MD1 <- c(medianx + 2*madx)
>>> MD2 <- c(medianx - 2*madx)
>>> out1[i] <- which(getdata[,i] > MD1) # store data that are
>>> greater than median + 2 mad
>>> out2[i] <- which (getdata[,1] < MD2) # store data that are
>>> greater than median - 2 mad
>>> resultdf <- data.frame(out1, out2)
>>> write.table (resultdf, "out.csv", sep=",")
>>> }
>>>
>>>
>>> My idea here is to store those value which are either greater than median
>>> +
>>> 2 *MAD or less than median - 2*MAD. Each variable have different length of
>>> output.
>>>
>>> The following last error message:
>>> Error in data.frame(out1, out2) :
>>> arguments imply differing number of rows: 2, 0
>>> In addition: Warning messages:
>>> 1: In out1[i] <- which(getdata[, i] > MD1) :
>>> number of items to replace is not a multiple of replacement length
>>> 2: In out2[i] <- which(getdata[, 1] < MD2) :
>>> number of items to replace is not a multiple of replacement length
>>> 3: In out1[i] <- which(getdata[, i] > MD1) :
>>> number of items to replace is not a multiple of replacement length
>>>
>>> Thank you in advance for helping me.
>>>
>>> Best regards;
>>> RHS
>>>
>>> [[alternative HTML version deleted]]
>>>
>>> ______________________________________________
>>> R-help@r-project.org mailing list
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide
>>> http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>>
>>
>>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
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