Hi,
> returns.z = tail(prices.z,-1)/head(prices.z,-1) - 1 # should be equivalent > to returns = exp(diff(log(prices.z))) - 1 > > Curiously, I get a zoo object back with zeros everywhere and also with the > index having one fewer element than it should. > > Does anyone know how to pointwise divide zoo objects, and what exactly "/" > is doing? > I think any arithmetic operations on zoo objects work on values having the same indexes. So if x <- zoo(1:10, 1:10) y <- zoo(1:10, 11:20) x/y # no result as no elements have the same index y <- zoo(1:10, 6:15) x/y # last five elements from x, first five from z To do your first example, you can use coredata so that one of your obejcts would be an ordinary vector: returns.z = tail(prices.z,-1)/coredata(head(prices.z,-1)) - 1 Regards, Kenn [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.