On Mar 12, 2011, at 3:08 PM, algotr8der wrote:
I am new to R so I apologize if my question is trivial. I have not
been able
to figure out whether what I want to do is even possible.
I have a data frame of stock ticker symbols which I store into R
space from
a txt file as follows:
tickers <- read.csv("stocks.txt", header=FALSE, sep=",")
tickers <- tickers[1] / the tickers are stored in the first column
tickers
V1
1 BCSI
2 WBSN
3 NTAP
4 FFIV
5 SU
is.vector(tickers)
[1] FALSE
is.data.frame(tickers)
[1] TRUE
I tried to do the following without success.
stockdata <- data.frame()
stockdata <- coredata(get.hist.quote(instruments=tickers,
start="2011-01-01", end="2011-01-31", quote=c("Close"),
provider="yahoo"))
Error in get.hist.quote(instruments = tickers, start = "2011-01-01",
end =
"2011-01-31", :
unused argument(s) (instruments = tickers)
So I coerced the data stored in 'tickers' to be a character as
follows:
as.character(tickers)
No, you did not. You need to make an assignment of any result, AND you
need to reference the column name:
tickers$V1 <- as.character(tickers$V1)
You should also have reference the package from which get.hist.quote
was being used.
--
david.
Then I tried to execute get.hist.quote as above with the same erro.
stockdata <- coredata(get.hist.quote(instruments=tickers,
start="2011-01-01", end="2011-01-31", quote=c("Close"),
provider="yahoo"))
Error in get.hist.quote(instruments = tickers, start = "2011-01-01",
end =
"2011-01-31", :
unused argument(s) (instruments = tickers)
I dont want to use loops because of inefficiencies. I know in Matlab
I can
take advantage of the matrix/vector environment by passing a
variable as a
vector. I think there should be a clean way to do what I want to do.
I have
1500+ tickers and I dont want to cycle through each of them in a loop.
I would greatly appreciate some guidance.
--
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David Winsemius, MD
West Hartford, CT
______________________________________________
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