I'm having a function of the form 1> f<-function(x){ 1+ 1+ return(x^p) 1+ 1+ }
,and I would like to integrate it with respect to x, where p should be any constant. One way would be to set a value for p globally and then call integrate function: p=2 integrate(f, lower = -1, upper = 1) However, I would like to use 'integrate' inside a function, so I could call it passing p as a parameter. I tried something like this: 1> p=1 1> integral<-function(p){ 1+ integrate(f, lower = -1, upper = 1) 1+ 1+ } 1> 1> integral(2) 0 with absolute error < 1.1e-14 ,but it doesn't work as the integral of f is evaluated with p=1 (the value of the global variable p) and not with the value of p=2 when the function integral is called. Does anyone knows how can I solve this problem? Thanks in advance santiagorf -- View this message in context: http://r.789695.n4.nabble.com/integrate-a-fuction-tp3336066p3336066.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.