On Wed, Mar 2, 2011 at 9:36 AM, ivo welch <ivo.we...@gmail.com> wrote:
> thanks, Henrique. did you mean
>
> as.vector(t(mapply(function(x, f)f(x), split(t, ((t %% 2)==0)),
> list(f, g)))) ?
>
> otherwise, you get a matrix.
>
> its a good solution, but unfortunately I don't think this can be used
> to redefine ifelse(cond,ift,iff) in a way that is transparent. the
> ift and iff functions will always be evaluated before the function
> call happens, even with lazy evaluation. :-(
>
> I still think that it makes sense to have a smarter vectorized %if% in
> a vectorized language like R. just my 5 cents.
>
Ivo,
There is no guarantee in general that f(x[3,5,7]) is the same as f(x)[3,5,7]
-thomas
--
Thomas Lumley
Professor of Biostatistics
University of Auckland
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