Dear Vincy,
Try this:
C[is.nan(C)] <- 0
HTH,
Ivan
Le 2/28/2011 13:10, Vincy Pyne a écrit :
Dear R helpers
I seem to have one trivial problem but can't find solution to it.
Suppose I have following input.
A = c(1, 3, 0, 5, 8) # 3rd element is 0
B = c(100, 30, 0, 25, 40) # 3rd element is 0
C = A/B
C
[1] 0.01 0.10 NaN 0.20 0.20
Obviously, I can't divide 0/0 and hence NaN. My problem is how to replace this
NaN say by 0.
So that I can have C as
C = c(0.01, 0.10, 0, 0.20, 0.20)
I tried the replace command but can't get rid of NaN.
Kindly guide.
Vincy
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