Description:
'lapply' returns a list of the same length as 'X', each element of
which is the result of applying 'FUN' to the corresponding element
of 'X'.
I expect that when I do
> lapply(vec,f)
f would be called _once_ for each component of vec.
this is not what I see:
parse.num <- function (s) {
cat("parse.num1\n"); str(s)
s <- as.character(s)
cat("parse.num2\n"); str(s)
if (s == "N/A") return(s);
as.numeric(gsub("M$","e6",gsub("B$","e9",s)));
}
> vec
mcap
1 200.5B
2 19.1M
3 223.7B
4 888.0M
5 141.7B
6 273.5M
7 55.649B
> str(vec)
'data.frame': 7 obs. of 1 variable:
$ mcap: Factor w/ 7 levels "141.7B","19.1M",..: 3 2 4 7 1 5 6
> vec<-lapply(vec,parse.num)
parse.num1
Factor w/ 7 levels "141.7B","19.1M",..: 3 2 4 7 1 5 6
parse.num2
chr [1:7] "200.5B" "19.1M" "223.7B" "888.0M" "141.7B" "273.5M" ...
Warning message:
In if (s == "N/A") return(s) :
the condition has length > 1 and only the first element will be used
i.e., somehow parse.num is called on the whole vector vec, not its
components.
what am I doing wrong?
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