Sorry.. my bad.. I should have done z = lapply(z, as.numeric) That works. Shank
From: Khanvilkar, Shashank Sent: Wednesday, February 09, 2011 1:33 PM Cc: r-help@r-project.org Subject: RE: [R] Question on sapply Thanks, Nopes.. Does not seem to work. > lapply(z, as.numeric) [[1]] [1] 1 1 [[2]] [1] 2 2 [[3]] [1] 3 3 [[4]] [1] 4 4 > typeof(z[[1]][1]) [1] "character" Shank From: Henrique Dallazuanna [mailto:www...@gmail.com] Sent: Wednesday, February 09, 2011 12:34 PM To: Khanvilkar, Shashank Cc: r-help@r-project.org Subject: Re: [R] Question on sapply Try this: lapply(z, as.numeric) On Wed, Feb 9, 2011 at 5:16 PM, Khanvilkar, Shashank <skhan...@qualcomm.com<mailto:skhan...@qualcomm.com>> wrote: Hello All, Thanks in advance for all help I have the following vector of strings that I want to split.. > y = c("1/1","2/2", "3/3", "4/4") > y [1] "1/1" "2/2" "3/3" "4/4" > z = strsplit(y,"/") > z [[1]] [1] "1" "1" [[2]] [1] "2" "2" [[3]] [1] "3" "3" [[4]] [1] "4" "4" Now how do I convert all elements of z to an interger.. (currently t, it is of type character) I believe sapply is the correct function, but don't know what the syntax is. Thanks Shank [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org<mailto:R-help@r-project.org> mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
