Thanks David - but '1' (if I understood correctly) returns the same value for
each row, which I took to be an error.
nt
V1 V2 V3 V4 V5 V6
1 24.71 23.56 24.71 23.56 24.71 23.56
2 25.64 25.06 25.64 25.06 25.64 25.06
3 21.29 20.87 21.29 20.87 21.29 20.87
4 25.92 26.92 25.92 26.92 25.92 26.92
5 24.36 23.60 24.36 23.60 24.36 23.60
6 24.91 24.32 24.91 24.32 24.91 24.32
7 23.56 23.14 23.56 23.14 23.56 23.14
8 23.94 23.99 23.94 23.99 23.94 23.99
9 26.65 26.07 26.65 26.07 26.65 26.07
test <- apply(nt, 1, shapiro.test)
> fred<-data.frame(sapply(test,function(x)c(x$statistic, x$p.value)))
> fred
X1 X2 X3 X4 X5 X6
X7 X8 X9
W 0.682676792 0.682676792 0.682676792 0.682676792 0.682676882 0.682676792
0.682676792 0.682676792 0.682676792
0.004039347 0.004039347 0.004039347 0.004039347 0.004039358 0.004039347
0.004039347 0.004039347 0.004039347
Version details are below:
R.Version()
$platform
[1] "x86_64-apple-darwin9.8.0"
$arch
[1] "x86_64"
$os
[1] "darwin9.8.0"
$system
[1] "x86_64, darwin9.8.0"
$status
[1] ""
$major
[1] "2"
$minor
[1] "12.0"
$year
[1] "2010"
$month
[1] "10"
$day
[1] "15"
$`svn rev`
[1] "53317"
$language
[1] "R"
$version.string
[1] "R version 2.12.0 (2010-10-15)"
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