On Jan 31, 2011, at 1:03 PM, Bogaso Christofer wrote:
Dear all, let say I have following data frame:
> dfrm <- data.frame(x=rnorm(18), y=rep(c("a", "b", "c"), each=6))
> tapply(dfrm$x, dfrm$y, c)
$a
[1] 0.9711995 1.4018345 -1.4355713 -0.5106138 -0.8470171
[6] 1.1634586
$b
[1] -0.8058164 0.4977112 1.1556391 0.8158588 0.2549273
[6] 3.0758260
$c
[1] 0.437345128 -0.415874363 0.003230285 -0.737117910
[5] 1.247972964 0.903001077
data.frame(x=rnorm(18), y=rep(c("a", "b", "c"), each=6))
x y
1 -1.072152537 a
2 0.382985265 a
3 0.058877377 a
4 -0.006911939 a
5 -2.355269051 a
6 -0.303095553 a
7 0.484038422 b
8 0.733928931 b
9 -1.136014346 b
10 0.503552090 b
11 1.708609658 b
12 -0.294599403 b
13 1.239308497 c
14 0.754081946 c
15 -0.237346858 c
16 -0.051011439 c
17 -0.618675146 c
18 0.537612359 c
From this data frame I want to create a "list" of length 3, where
each
element of this list will be a vector corresponding to the value of
y. For
example, 1st element will be all "x" values corresponding to the
"y=a", and
similarly the other elements of this list. Can somebody point me how
to do
this without having some "for" loop?
Thanks and regards,
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and provide commented, minimal, self-contained, reproducible code.