sapply(z, function(row) ...) does not actually grab a row at a time out of
'z'. It grabs a column (because 'z' is a data.frame)

You may want:
t(apply(z, 1, function(row) row - means))

or:

t(t(z) - means)


Hope that helps,

-David Johnston
-- 
View this message in context: 
http://r.789695.n4.nabble.com/sapply-puzzlement-tp3243520p3243534.html
Sent from the R help mailing list archive at Nabble.com.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to