sapply(z, function(row) ...) does not actually grab a row at a time out of 'z'. It grabs a column (because 'z' is a data.frame)
You may want: t(apply(z, 1, function(row) row - means)) or: t(t(z) - means) Hope that helps, -David Johnston -- View this message in context: http://r.789695.n4.nabble.com/sapply-puzzlement-tp3243520p3243534.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
