Although I saw this issue being discussed many times before, I still did not find the answer to: why does R can not calculate p-values for data with ties (i.e. - sample with two or more values the same)?
Can anyone elaborate some details about how does R calculate the p- values for the Kolmogorov Smirnov test statistics? I can understand the theoretical problem that continuous distributions do not generate ties, but again - why isn't it possible to calculate accurate p-values with ties? how does it work? what is the procedure to calculate p-values for the Kolmogorov Smirnov test statistics? Thank you advance, Saray -- View this message in context: http://r.789695.n4.nabble.com/How-to-calculate-p-value-for-Kolmogorov-Smirnov-test-statistics-tp3238293p3238293.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
