Hi
r-help-boun...@r-project.org napsal dne 24.01.2011 23:18:35:
> Thanks for the reply Erik, As you mentioned, grouping consecutive
elements
> of 'a' was my idea.
> I am unaware of any R'ish way to do it. It would be nice if someone in
the
> community knows this.
>
> The error resulting in the NA was pretty easy to fix, and my loop works,
but
> the results are still wrong (new script below).
> Ideally it should print single "hello" for the single letters and
grouped '3
> hellos' for the fives, grouped '2 hellos' for the sixes etc.
>
> Based on the run results, if the value of n is being tracked, it changes
> quite unpredictably.
> Can someone explain how the value of n changes from end of the loop to
the
> top without anything being done to it?
Put it into a foo function and make use debug(fun())
Regards
Petr
BTW mapply solution is shorter and probably quicker and easier to
maintain.
> I cannot figure out what I am doing wrong.
>
> a<-c(2,3,5,5,5,6,6,7)
>
> for(n in 1:length(a))
> {
> print(paste("n: ",n))
> z1<-a[n]
> print(paste("z1:",z1))
> #make a list container
> ldata<-list()
> t=1
>
> while(z1==a[n])
> {
>
> #add dataframes to list
> ldata[[t]]<-paste("hello")
>
> n=n+1
> t=t+1
>
> if(n>length(a))
> {
> break;
> }
> }
> print("------End of while loop-------")
>
> for(y in 1:length(ldata))
> {
> print(ldata[[y]])
> }
>
> print(paste("n: ",n))
> print("******End of for loop********")
> }
>
>
> Thanks,
> Roy
>
> [[alternative HTML version deleted]]
>
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