If you haven't got so much data a loop should do:
while(sum(duplicated(x))>0) #if this condition is TRUE then there are still
duplicates in x
{
x[duplicated(x)] <- x[duplicated(x)]+0.01 #using duplicated(x) to
index the x vector
}
Hope this helps,
Regards
Moritz
____________________
Moritz Grenke
http://www.360mix.de
-----Ursprüngliche Nachricht-----
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von Ortiz, John
Gesendet: Donnerstag, 20. Januar 2011 16:13
An: r-help@r-project.org
Betreff: [R] Identify duplicate numbers and to increase a value
Hi everybody.
I want to identify duplicate numbers and to increase a value of 0.01 for
each time that it is duplicated.
Example:
x=c(1,2,3,5,6,2,8,9,2,2)
I want to do this:
1
2 + 0.01
3
5
6
2 + 0.02
8
9
2 + 0.03
2 + 0.04
I am trying to get something like this:
1
2.01
3
5
6
2.02
8
9
2.03
2.04
Actually I just know the way to identify the duplicated numbers
rbind(x, duplicated(x) | duplicated(x, fromLast=TRUE))
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
x 1 2 3 5 6 2 8 9 2 2
0 1 0 0 0 1 0 0 1 1
Some advice?
Thanks and regards
John Ortiz
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
