Hi,
I have just recently started to use regular expression, so I'm not sure
that my solution would be valid in every case. But it works in yours:
> unlist(strsplit(output, split=" +"))
[1] "a" "b" "8888" "6"
It would split them whatever the number of spaces between them is
(because of the "+" in the pattern of splitting).
HTH,
Ivan
Le 12/14/2010 14:32, Scott Chamberlain a écrit :
Hello,
I am attempting to manipulate strings in which there are differing amounts
of whitespace before and after each element taht I want to keep (any word,
letter, or number). However, after strsplit and unlist, I know how to select
specific elements with "[ ]", but I want to select instead all elements that
are not missing. That is, do not select any elements that are simply "".
output<- c("a b 8888 6")
gsub(" ","",unlist(strsplit(output," ",fixed=TRUE)))
[1] "a" "" "b" "8888" "" "" "6"
Thanks! Scott Chamberlain
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