It sounds like you want to use a "list" instead of a dataframe,
especially if the elements are a different length.
> d <- list() # initialize
> d[[length(d) + 1]] <- list() # extend
> d[[length(d)]]$fun <- sin # add a function
> d[[length(d) + 1]] <- list() # extend again
> d[[length(d)]]$fun <- cos # another function
> d[[length(d)]]$val <- 42 # some value
> d
[[1]]
[[1]]$fun
function (x) .Primitive("sin")
[[2]]
[[2]]$fun
function (x) .Primitive("cos")
[[2]]$val
[1] 42
On Wed, Dec 8, 2010 at 5:08 AM, Rainer M Krug <r.m.k...@gmail.com> wrote:
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> Hi
>
> I would like to have a data.frame, where one column contains functions,
> and another one lists. i.e.:
>
> FUN <- function(l) {return(l$a+l$b+l$c}
> LIST <- list(a=1, b=2, c=3)
>
> d <- data.frame(fun=FUN, no=LIST, value=2, b=TRUE)
>
> FUN <- function(l) {return(l$a*l$b*l$c}
> LIST <- list(a=4, b=5, c=6)
>
> d <- rbind(d, data.frame(fun=FUN, no=LIST, value=2, b=FALSE)
>
> I would like
> d$FUN[1](d$l[1] == 6
> to be TRUE
>
> I want to use it to save a parameterset for a simulation model, which
> consists of functions, lists, and vectors of different length.
>
> Is this possible?
>
>
> Cheers,
>
> Rainer
>
> - --
> Rainer M. Krug, PhD (Conservation Ecology, SUN), MSc (Conservation
> Biology, UCT), Dipl. Phys. (Germany)
>
> Centre of Excellence for Invasion Biology
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> email: rai...@krugs.de
>
> Skype: RMkrug
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>
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
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