Hi Hadley: I was trying to use ddply using the format . (var1) for splitting.
I thought . ( as.name(grp) ) would do the same thing. But it does not. I was just trying to know my mistake. I am sorry if it is a basic question. Thank you and others for your reply. Best Regards, S. On Mon, Dec 6, 2010 at 5:28 PM, Hadley Wickham <had...@rice.edu> wrote: > On Mon, Dec 6, 2010 at 3:58 AM, Sunny Srivastava > <research.b...@gmail.com> wrote: > > Dear R-Helpers: > > > > I am using trying to use *ddply* to extract min and max of a particular > > column in a data.frame. I am using two different forms of the function: > > > > > > ## var_name_to_split is a string -- something like "var1" which is the > name > > of a column in data.frame > > > > ddply( df, .(as.name(var_name_to_split)), function(x) c(min(x[ , 3] , > max(x[ > > , 3]))) ## fails with an error - case 1 > > ddply( df, var_name_to_split , function(x) c(min(x[ , 3] , max(x[ , 3]))) > > ## works fine - case 2 > > > > I can't understand why I get the error in case 1. Can someone help me > > please? > > Why do you expect case 1 to work? > > Hadley > > -- > Assistant Professor / Dobelman Family Junior Chair > Department of Statistics / Rice University > http://had.co.nz/ > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
