Well, there's the obvious:
N = matrix(0,n-1,n-1)
for(i in 2:(n-1))
N[1,i] = 1/(pi * (i-1))
for(i in 2:(n-2))
for(j in i:(n-1))
N[i,j] = N[i-1,j-1]
for(i in 2:(n-1))
for(j in 1:i)
N[i,j] = -N[j,i]
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
Hello,
I'm trying to write the following matlab code into R:
N = zeros(n-1); for i=2:(n-1)
N(1,i) = 1/(pi * (i-1));
end for i=2:(n-2)
for j=i:(n-1) N(i,j) = N(i-1,j-1);
end;
end for i=2:(n-1)
end
for j=1:i N(i,j) = -N(j,i);
end;
any suggestions?
Thanks
can i just add the following line to my calculation N=1/(pi*(i-1)
--
Marcelo Andrade de Lima
UNIFESP - Universidade Federal de S?o Paulo
Departamento de Bioqu?mica
Disciplina de Biologia Molecular
Rua Tr?s de Maio 100, 4 andar - Vila Clementino, 04044-020
Lab +55 11 55764438 R.1188
Cell +55 11 92725274
ml...@unifesp.br
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