I always find R useful to solve problems like this:
dummy = as.numeric(cleary$D1 %in% c(4,6,7))
If, for some reason you want to use a loop, try
dummy <- matrix(NA, nrow=nrow(cleary), ncol=1)
for (i in 1:length(cleary$D1)){
if (cleary$D1[i] %in% c(4,6,7)){dummy[i] = 1}
else {dummy[i] = 0}
}
When you write a loop, you need to use the loop index
to select the individual value you're working with.
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Mon, 18 Oct 2010, gravityflyer wrote:
Hi everyone,
I've got a dataset with 12,000 observations. One of the variables
(cleary$D1) is for an individual's country, coded 1 - 15. I'd like to create
a dummy variable for the Baltic states which are coded 4,6, and 7. In other
words, as a dummy variable Baltic states would be coded 1, else 0. I've
attempted the following for loop:
dummy <- matrix(NA, nrow=nrow(cleary), ncol=1)
for (i in 1:length(cleary$D1)){
if (cleary$D1 == 4){dummy[i] = 1}
else {dummy[i] = 0}
}
Unfortunately it generates the following error:
1: In if (cleary$D1 == 4) { ... :
the condition has length > 1 and only the first element will be used
Another options I've tried is the following:
binary <- vector(length=length(cleary$D1))
for (i in 1:length(cleary$D1)) {
if (cleary$D1 == 4 | cleary$D1 == 6 | cleary$D1 == 7 ) {binary[i] = 1}
else {binary[i] = 0}
}
Unfortunately it simply responds with "syntax error".
Any thoughts would be greatly appreciated!
--
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