On 10/14/2010 2:53 PM, li li wrote:
Dear all,
I have a function f(x) which return a list as result.
$T1
[1] 0.03376190
$T2
[1] 0.04725
$T3
[1] 0.3796071
$T4
[1] 0.3713452
$T5
[1] 0.4523651
$T6
[1] 0.4575873
I now find the result for a vector of x values at one time. I want to
store the reuslt
for each xi value in a column of a matrix
x<- seq(0,1, by=0.1)
result<- matrix(0, nrow=6, ncol=length(x))
for (i in 1:length(x)){result[,i]<- f(x[i])}
It is not working. Can some help me.
Thank you very much!
Hannah
In order to test my solution, I needed a function that returned
something of the structure you had.
f <- function(x) {
r <- as.list(rnorm(6))
names(r) <- paste("T",1:6,sep="")
r
}
Using that, you can replace the for loop with:
for (i in 1:length(x)){result[,i] <- unlist(f(x[i]))}
The problem is that f returns a list; you can only put a vector in part
of a matrix. unlist() takes care of that conversion.
--
Brian S. Diggs, PhD
Senior Research Associate, Department of Surgery
Oregon Health & Science University
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