Dennis,
Thanks for that. The problem now is that I am trying to use it in a for
loop. Based on the example before, 2 entries are required after H[3] as
specified by O. The problem is that when inserting values the length of the
array changes so I don't know how to tell the loop that. This is what I
have:
for (i in 1:length(H)) {
if (o[i]>0) {append(H, -1, after = i-1)}
}
Any ideas how to create a loop that allows the inclusion of more than 1
value?
Cheers,
Doug
djmuseR wrote:
>
> Hi:
>
> Perhaps
>
> ?append
>
> for simple insertions...
>
> HTH,
> Dennis
>
> On Wed, Oct 13, 2010 at 1:24 AM, dpender <d.pen...@civil.gla.ac.uk> wrote:
>
>>
>> R community,
>>
>> I am trying to write a code that fills in data gaps in a time series. I
>> have no R or statistics background at all but the use of R is proving to
>> be
>> a large portion of my PhD research.
>>
>> So far my code identifies where and the number of new entries required
>> but
>> I
>> do not know how to add additional rows or columns into an array. Any
>> advice
>> on how this can be done?
>>
>> Here is an example:
>>
>> H [0.88 0.72 0.89 0.93 1.23 0.86]
>> T [7.14 7.14 7.49 8.14 7.14 7.32]
>> O [0 0 0 2 0 0]
>>
>> This says that in order to complete the data set 2 entries are required
>> prior to H[4] and T[4] i.e. where O = 2.
>>
>> Thanks,
>>
>> Doug
>> --
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>>
>> ______________________________________________
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>>
>
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>
> ______________________________________________
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>
>
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