Hello Julia,
Your loop is just "overwriting" your variables each time.
Is this the sort of thing you want ?
# make a matrix with 10 cols of N random uniform values
N <- 5
x <- t( replicate( 10, runif(N, 0, 1) ) )
You can leave out the t( ... ) part if you want the randomizations to
be rows instead of cols
Michael
On 6 October 2010 20:51, Julia Lira <julia.l...@hotmail.co.uk> wrote:
>
> Dear all,
>
>
>
> I need to do a loop in R, but I am not sure the software is generating "n"
> times the variables I request differently. When I ask to print the last
> matrix created, I just can see the loop for n=1.
>
> To be more precise, supose I need to simulate 10 times one variable and I
> want to fit the 10 variables simulated in a matrix. I dont really know what I
> am doing wrong, but I just can see 1 variable created.
>
> Below follows an example of what I want:
>
>
>
> rm(list=ls()) #remove almost everything in the memory
>
>
>
> set.seed(180185)
>
>
>
> #loop: create 10 times the variables (u1,u2,u3,u4,u5)
>
>
>
> for (i in 1:10){
> u1 <- c(runif(200,0,1))
> u2 <- c(runif(200,0,1))
> u3 <- c(runif(200,0,1))
> u4 <- c(runif(200,0,1))
> u5 <- c(runif(200,0,1))
> u <- c(u1,u2,u3,u4,u5)
> mu <- matrix(u, nrow=1000, ncol=1)
> }
>
>
> As you can see, when I print(mu), I just can see a matrix with the vector u
> in one column. I also tried to increase the number of columns to 10 (or i),
> but the matrix will have 10 times the same vector. And what I need is like a
> Monte Carlo simulation, where I have to simulate 10 times the variables above.
>
>
>
> Am I doing something wrong?
>
>
>
> Thanks in advance!
>
>
>
> Julia
>
> [[alternative HTML version deleted]]
>
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>
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