Hi Andrew, You can use duplicated() to index the rows you wish to keep, like this:
test.dat <- data.frame(a=c(1,1:5,5:10), b=1:12, c=letters[1:12]) #make up data duplicated(test.dat$a) # see what duplicated() function does !duplicated(test.dat$a) # see how we can invert using the ! function so that we get non-duplicated test.dat[!duplicated(test.dat$a),] # this is the important bit: use indexing to select non-duplicated rows. Best, Ista On Wed, Sep 22, 2010 at 12:35 PM, AndrewPage <savejar...@yahoo.com> wrote: > > I understand how duplicated and unique work for a list where all parts of a > given row are duplicated, or how to find duplicated values if I'm just > looking at that first column, but in this case the rows for 1954 and 1955 > are not completely the same; only quarter 1 is duplicated, so I'm not sure > how to apply either duplicated or unique in that case. > > Thanks, > Andrew > -- > View this message in context: > http://r.789695.n4.nabble.com/Unique-subsetting-question-tp2550453p2550651.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Ista Zahn Graduate student University of Rochester Department of Clinical and Social Psychology http://yourpsyche.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
