I would like to thank you again for your help.
But it seems that the floor function (ceiling, round too) create more dots in 
the matrix that line really "touches".

unique( floor( cbind( seq(2,62, by=0.1), linefn(seq(2,62, by=0.1)) ) )  ) 

You can see that in the picture below

http://yfrog.com/5blineswj

So, how to select the only the cells that the line "touches"?

I would like to thank you in advance for your help
best Regards
Alex




________________________________
From: David Winsemius <dwinsem...@comcast.net>

Cc: Rhelp list <r-help@r-project.org>
Sent: Wed, September 15, 2010 1:55:10 PM
Subject: Re: [R] Interpolate? a line


On Sep 15, 2010, at 7:24 AM, David Winsemius wrote:

> Replacing context:
> 
>>> Hello everyone.
>>> I have created a 100*100 matrix in R.
>>> Let's now say that I have a line that starts from (2,3) point and ends to 
the
>>> (62,34) point. In other words this line starts at cell (2,3) and ends at 
cell
>>> (62,34).
>>> 
>>> Is it possible to get by some R function all the matrix's cells that this 
>line
>>> transverses?
>>> 
>>> I would like to thank you for your feedback.
>>> 
>>> Best Regards
>>> Alex
> 
> On Sep 15, 2010, at 6:52 AM, Michael Bedward wrote:
> 
>> Hello Alex,
>> 
>> Here is one way to do it. It works but it's not pretty :)
> 
> If you want an alternative, consider that produces the Y cell indices (since 
>the x cell indices are already 2:62):
> 
> > linefn <- function(x) 3+((34-3)/(62-2)) *(x-2)
> > findInterval(linefn(2:62), 3:34)
> [1]  1  1  2  2  3  3  4  4  5  5  6  6  7  7  8  8  9  9 10 10 11 11 12 12 
> 13 
>13 14
> [28] 14 15 15 16 17 17 18 18 19 19 20 20 21 21 22 22 23 23 24 24 25 25 26 26 
> 27 
>27 28
> [55] 28 29 29 30 30 31 32
> # that seems "off" by two
> > linefn(62)
> [1] 34
> > linefn(2)
> [1] 3 # but that checks out and I realized those were just indices for the 
> 3:34 
>findInterval vector
> 
> > (3:34)[findInterval(linefn(2:62), 3:34)]
> [1]  3  3  4  4  5  5  6  6  7  7  8  8  9  9 10 10 11 11 12 12 13 13 14 14 
> 15 
>15 16
> [28] 16 17 17 18 19 19 20 20 21 21 22 22 23 23 24 24 25 25 26 26 27 27 28 28 
> 29 
>29 30
> [55] 30 31 31 32 32 33 34
> 
> ( no rounding and I think the logic is clearer.)

But I also realized it didn't enumerate all the the cells were crossed either, 
only indicating which cell was associated with an integer value of x. Also 
would 
have even more serious problems if the slope were greater than unity. To 
enumerate the cell indices that were crossed, try:

unique( floor( cbind( seq(2,62, by=0.1), linefn(seq(2,62, by=0.1)) ) )  )
      [,1] [,2]
[1,]    2    3
[2,]    3    3
[3,]    4    4
[4,]    5    4
[5,]    5    5
[6,]    6    5
[7,]    7    5
[8,]    7    6
snipping interior results
[83,]   58   32
[84,]   59   32
[85,]   60   32
[86,]   60   33
[87,]   61   33
[88,]   62   34

That could probably be passed to rect() to illustrate (and check logic):

rect(cellidxs[,1], cellidxs[,2], cellidxs[,1]+1, cellidxs[,2]+1, col="red")

#redraw line :
lines(2:62, 3+(34-3)/(62-2)*(0:60))


> 
> --David.
> 
>> 
>> interp <- approx(c(2, 62), c(3, 34), method="linear", xout=2:62)
>> m <- matrix(c(interp$x, round(interp$y)), ncol=2)
>> tie <- m[,2] == c(-Inf, m[-nrow(m),2])
>> m <- m[ !tie, ]
>> 
>> You might want to examine the result like this...
>> 
>> plot(m)  # plots points
>> lines(c(2,26), c(3, 34))  # overlay line for comparison
> you can add a grid with
> abline(v=2:62, h=3:34)
>> 
>> Michael
>> 
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
> 
> David Winsemius, MD
> West Hartford, CT
> 
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

David Winsemius, MD
West Hartford, CT


      
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