Hi, There is probably an easier way, but this will work:
ta[time(ta)==1965] With your data, I get: > ta[time(ta)==1965] [1] 6 HTH, Josh On Sat, Sep 4, 2010 at 9:08 PM, StatWM <[email protected]> wrote: > > Dear Community, > > say, I have an annual ts() object sampled from 1960 to 1969 like: > > ta<-ts(1:10, start=1960, frequency=1) > > How can I extract the value from the year 1965? > > I mean, not by: > > ta[6] > > but by something like: > > ta[1965] > > where I'm directly referring to the year of the observation? > > Thank you in advance! > > -- > View this message in context: > http://r.789695.n4.nabble.com/simple-ts-object-question-tp2527085p2527085.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Joshua Wiley Ph.D. Student, Health Psychology University of California, Los Angeles http://www.joshuawiley.com/ ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
