On Aug 28, 2010, at 12:29 AM, Cuckovic Paik wrote:
Thanks for respose.
you still used two steps to get the new matrix tst2:
For Pete"s sake! Can't you see that I didn't _need_ to use tst2. The
same operations would have worked on tst. I was just using tst2
because I wanted to be able to restore to the original site.
step 1: tst2 = tst
step 2: perform the row operation in tst2.
Can you do this in a single step?
Try it yourself, why not?
--
David
A similar example:
tst
[,1] [,2] [,3] [,4]
[1,] 1 5 9 13
[2,] 2 6 10 14
[3,] 3 7 11 15
[4,] 4 8 12 16
# I define a new matrix by deleting the first row and the first
column of
matrix tst using following single step:
New.tst=tst[-1,-1]
New.tst
[,1] [,2] [,3]
[1,] 6 10 14
[2,] 7 11 15
[3,] 8 12 16
# the original matrix tst is still .
tst
[,1] [,2] [,3] [,4]
[1,] 1 5 9 13
[2,] 2 6 10 14
[3,] 3 7 11 15
[4,] 4 8 12 16
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-define-new-matrix-based-on-an-elementary-row-operation-in-a-single-step-tp2341768p2344456.html
Sent from the R help mailing list archive at Nabble.com.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.