I too am unsure of what is required but another way is
gsub(",$","",gsub("[f53=]+","",a))
[1] "1,22"
Regards
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
ARMIDALE NSW 2351
Email home: mac...@northnet.com.au
At 21:47 26/08/2010, you wrote:
It isn't entirely clear what you are trying to do - your grep() statement
simply returns the entire string you started with.
But to turn that string into a vector, you will need some combination
of gsub(), strsplit(), and as.numeric() with the exact values depending
on the exact form of the output returned by grep. By c(1, 22) do you
mean a vector (my first assumption), or do you actually mean the
string "c(1, 22)"?
If the former, maybe something like this:
> x <- "f1=5,f22=3"
> x <- gsub("=[0-9]+", "", x)
> x
[1] "f1,f22"
> x <- gsub("f", "", x)
> x
[1] "1,22"
> x <- strsplit(x, ",")
> x
[[1]]
[1] "1" "22"
> x <- unlist(x)
> x
[1] "1" "22"
> x <- as.numeric(x)
> x
[1] 1 22
Sarah
On Thu, Aug 26, 2010 at 6:16 AM, Dimitri Shvorob
<dimitri.shvo...@gmail.com> wrote:
>
>> grep("f[0-9]+=", "f1=5,f22=3,", value = T)
> [1] "f1=5,f22=3,"
>
> How do I make the line output c("f1", "f22") instead? (Actually, c(1,22)
> would be even better).
>
> Thank you.
>
>
--
Sarah Goslee
http://www.functionaldiversity.org
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