This seems to work, although it eliminates the
sparseness of the storage:
dimnames(a) = list(NULL,letters[1:5])
as.data.frame(as.matrix(a))
a b c d e
1 0 0 0 1 0
2 2 1 0 0 0
3 0 0 3 0 1
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Thu, 19 Aug 2010, erickso...@aol.com wrote:
I am able to create a coordinate list sparse matrix this way:
r = c(1,2,2,3,3)
c = c(4,1,2,3,5)
v = c(1,2,1,3,1)
a = sparseMatrix(i=r,j=c,x=v)
However, this results in an object that looks like this:
a
3 x 5 sparse Matrix of class "dgCMatrix"
[1,] . . . 1 .
[2,] 2 1 . . .
[3,] . . 3 . 1
How do I convert this object into a data.frame that would look like this:
data.frame(a=c(0,2,0),b=c(0,1,0),c=c(0,0,3),d=c(1,0,0),e=c(0,0,1))
a b c d e
1 0 0 0 1 0
2 2 1 0 0 0
3 0 0 3 0 1
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