Try this: colSums(apply(List_2, 1, is.element, List_1)) > 0
On Tue, Aug 10, 2010 at 5:42 PM, GL <pfl...@shands.ufl.edu> wrote: > > Know that if I have List_1 and List_2 that I can check to see if the > intersect via the code below: > > List _1: > a, b, c, d, e, f, g > List_2: > z, y, x, w, v, u, b > length(intersect(List_1, List_2)) > 0 > return = true > > If instead I wanted to check a dataframe that is a "list of lists," how > would I do that by record without looping? > > List _1: > a, b, c, d, e, f, g > > List_2: > z, y, x, w, v, u, b > y, z, w, v, v, u, m > z, y, x, a, b, c > . > . > . > > return > true > false > true > , > , > , > > -- > View this message in context: > http://r.789695.n4.nabble.com/Intersecting-list-vs-rows-in-matrix-tp2320427p2320427.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
