Hi all,
I would like to flag each record in the data according to certain conditions
as specified below.
For example,
If "Close_date" in *dat* is between ("Open" & "Close") or ("Open1" &
"Close1") or ("Open2" & "Close2") in *oc, *flag the records as "Valid",
otherwise "Invalid"
I would like to use sapply family functions if possible due to the nature of
large data set.
ini <- as.Date("2010/1/1", "%Y/%m/%d")
# Generate arbitrary data frame consisting of date values
oc <- data.frame(Open = seq(ini, ini + 5, 1), Close = seq(ini + 365, ini +
365 + 5, 1), Open1 = seq(ini + 365*2, ini + 365*2 + 5, 1), Close1 = seq(ini
+ 365*3, ini + 365*3 + 5, 1), Open2 = seq(ini + 365*4, ini + 365*4 + 5, 1),
Close2 = seq(ini + 365*5, ini + 365*5 + 5, 1))
rownames(oc) <- c("AAA", "AA", "A", "BBB", "BB", "B")
oc
Open Close Open1 Close1
Open2 Close2
AAA 2010-01-01 2011-01-01 2012-01-01 2012-12-31 2013-12-31
2014-12-31
AA 2010-01-02 2011-01-02 2012-01-02 2013-01-01 2014-01-01
2015-01-01
A 2010-01-03 2011-01-03 2012-01-03 2013-01-02 2014-01-02
2015-01-02
BBB 2010-01-04 2011-01-04 2012-01-04 2013-01-03 2014-01-03
2015-01-03
BB 2010-01-05 2011-01-05 2012-01-05 2013-01-04 2014-01-04
2015-01-04
B 2010-01-06 2011-01-06 2012-01-06 2013-01-05 2014-01-05
2015-01-05
dat <- data.frame(Class = c("AAA", "C", "CC", "BB", "B", "A"), Close_date =
c(ini, ini, ini, ini+109, ini+39, ini+24), stringsAsFactors = FALSE)
dat
Class Close_date
1 AAA 2010-01-01
2 A 2010-01-01
3 CC 2010-01-01
4 BB 2010-04-20
5 B 2010-02-09
6 A 2010-01-25
Desired result is:
Class Close_date Flag
1 AAA 2010-01-01 Valid
2 A 2010-01-01 Invalid
3 CC 2010-01-01 Valid
4 BB 2010-04-20 Valid
5 B 2010-02-09 Valid
6 A 2010-01-25 Valid
The following seems to be a failure..
for (i in length(ind)) {
dat[["Flag"]] <- sapply(dat$Close_date, function(x) ifelse((x >=
oc[ind[i], 1] & x < oc[ind[i], 2]) | (x >= oc[ind[i], 3] & x < oc[ind[i],
4]) | (x >= oc[ind[i], 5] & x < oc[ind[i], 6]) | (x >= oc[ind[i], 7] & x <
oc[ind[i], 8]), "Valid", "Invalid"))
}
Any resolution in this would be greatly appreciated.
Many thanks in advance.
--
Steven
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