Try this,
source("http://gridextra.googlecode.com/svn/trunk/inst/test/expressions.r";)
library(grid)
e = expression(p[Wilcoxon], "<"*2.2%*%10^{-16})
grid.expr(e)
HTH,
baptiste
On Aug 4, 2010, at 9:56 AM, Johannes Graumann wrote:
> Hi Baptiste,
>
> This is, I fear a bit beyond my level of competency ... What I want to be
> able
> to do is things like put "<2.2%*%10^{-16}" in a table cell, who's name I can
> already set to "p[Wilcoxon]" ...
>
> Joh
>
> On Wednesday 04 August 2010 09:15:43 you wrote:
>> Hi,
>>
>> I don't know the answer to your question (how to make a data.frame with
>> expressions), but if you have a list of expressions you could try the
>> following,
>>
>> http://code.google.com/p/gridextra/wiki/testExpressions
>>
>> I'm open to suggestions for your original query (what is the best way to do
>> it – parse each string and coerce it as an expression?)
>>
>> HTH,
>>
>> baptiste
>>
>> On Aug 4, 2010, at 12:05 AM, Johannes Graumann wrote:
>>> Hi,
>>>
>>> Is there any way to get an expression into a data.frame, such that
>>> "grid.table" from "gridExtra" will plot it evaluated in the table body?
>>> The docu does it for the header, but is the body possible?
>>>
>>> Thanks, Joh
>>>
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