Thanks a lot! This solves my problem!
Joh On Monday 26 July 2010 17:06:37 Joshua Wiley wrote: > Hi, > > Here is another option if you already have a list you want to convert. > This will handle different elements of the list being different > lengths. > > #Using your example data > mydata <- list(c(1,2,3),c(4,5,6)) > > data.frame( > OriginalListIndex = rep(x = seq_along(mydata), > times = unlist(lapply(mydata, length))), > Item = unlist(mydata) > ) > > #Just to demonstrate that this method works generally > mydata <- list(c(1,2,3), c(7,6), c(3,4,5,6,7,8,9)) > > data.frame( > OriginalListIndex = rep(x = seq_along(mydata), > times = unlist(lapply(mydata, length))), > Item = unlist(mydata) > ) > > > HTH, > > Josh > > On Mon, Jul 26, 2010 at 7:46 AM, Johannes Graumann > > <johannes_graum...@web.de> wrote: > > Hi, > > > > Any ideas on how to efficiently convert > > > >> list(c(1,2,3),c(4,5,6)) > > > > to > > > >> data.frame(OriginalListIndex=c(1,1,1,2,2,2),Item=c(1,2,3,4,5,6)) > > > > Thanks for any hints, > > > > Joh > > > > ______________________________________________ > > R-help@r-project.org mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > > http://www.R-project.org/posting-guide.html and provide commented, > > minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
