Thanks all! That did it. On Thu, Jul 15, 2010 at 11:07 AM, Nikhil Kaza <nikhil.l...@gmail.com> wrote:
> Building on Erik's solution and because it would easier to do date > arithmetic.. > > d1 <- as.character(date) > d1 <- ifelse(nchar(d1)<4, paste(0,d1,sep=""),d1) > d2 <- as.Date(date, "%m%d") > > > On Jul 15, 2010, at 1:21 PM, btc1 wrote: > > >> Hello, I have a vector, "dates", as a series of 3 digit elements, i.e. > >> date >> [1] 528 528 528 528 528 528 528 528 528 528 528 528 708 708 708 708 708 >> 708 >> [19] 708 708 708 708 529 529 529 529 529 529 529 529 529 529 529 529 529 >> 529 >> [37] 529 624 >> >> I need to convert them into julian, but have to insert a "/" or "-" after >> the first number within each element of the vector (5/28 5/28 etc). Found >> plenty functions to replace by a pattern but not to cut by a certain >> number >> of digits with an element. Alternately, if I could run all the elements >> into >> one long vector and then cut every one then two digits, that would work as >> well. >> >> Thanks. >> -- >> View this message in context: >> http://r.789695.n4.nabble.com/Cut-a-within-elements-by-length-not-value-of-vectors-tp2290440p2290440.html >> Sent from the R help mailing list archive at Nabble.com. >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
