There's a bug in the code. If you add row names to the X matrix befor you call randomForest(), you'd get:
R> summary (outlier(mdl.rf) ) Min. 1st Qu. Median Mean 3rd Qu. Max. -1.0580 -0.5957 0.0000 0.6406 1.2650 9.5200 I'll fix this in the next release. Thanks for reporting. Best, Andy -----Original Message----- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Pau Carrio Gaspar Sent: Wednesday, July 14, 2010 6:36 AM To: r-help@r-project.org Subject: [R] randomForest outlier return NA Dear R-users, I have a problem with randomForest{outlier}. After running the following code ( that produces a silly data set and builds a model with randomForest ): ####################### library(randomForest) set.seed(0) ## build data set X <- rbind( matrix( runif(n=400,min=-1,max=1), ncol = 10 ) , rep(1,times= 10 ) ) Y <- matrix( nrow = nrow(X), ncol = 1) for( i in (1:nrow(X))){ Y[i,1] <- sign( sum ( X[i,])) } ## build model mdl.rf <- randomForest( x = X, y = as.factor(Y) , proximity=TRUE , mtry = 10 , ntree = 500) summary (outlier(mdl.rf) ) ####################### I get the following output: Min. 1st Qu. Median Mean 3rd Qu. Max. NA's 41 Can anyone explain why the output of outlier only returns NA's ? Thanks Pau [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Notice: This e-mail message, together with any attachme...{{dropped:11}} ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
