On Jul 12, 2010, at 5:45 PM, Felipe Carrillo wrote:
Thanks for the quick reply Duncan.
I don't think I have explained myself well, I have a dataset named
"report" and
my column headers are run1,run2,run3,run4 and so on.
I know how to access the data below those columns with
\Sexpr{report[1,1]} &
&\Sexpr{report[1,2]} and so on, but I can't access my column headers
with \Sexpr{} because I can't find the way to reference
run1,run2,run3 and run4.
Sorry if I am not explain myself really well.
Wouldn't this just be:
\Sexpr{names(report)} # ? or perhaps you want specific items in that
vector?
Sexpr{names(report)[1]}, Sexpr{names(report)[2]}, etc
--
David.
----- Original Message ----
From: Duncan Murdoch <murdoch.dun...@gmail.com>
To: Felipe Carrillo <mazatlanmex...@yahoo.com>
Cc: r-h...@stat.math.ethz.ch
Sent: Mon, July 12, 2010 2:18:15 PM
Subject: Re: [R] How to select the column header with \Sexpr{}
On 12/07/2010 5:10 PM, Felipe Carrillo wrote:
Hi:
Since I work with a few different fish runs my column headers change
everytime
I start a new Year. I have been using \Sexpr{} for my row and
columns and now
I am trying to use with my report column headers. \Sexpr{1,1} is
row 1 column 1,
what can I use for headers? I tried \Sexpr{0,1} but sweave didn't
like
it..Thanks in advance
for any hints
\Sexpr takes an R expression, and inserts the first element of the
result into
your text. Using just "0,1" (not including the quotes) is not a
valid R
expression.
You need to use paste() or some other function to construct the
label you want
to put in place, e.g. \Sexpr{paste(0,1,sep=",")} will give you "0,1".
Duncan Murdoch
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