Lauri Nikkinen wrote:
> Hi R-users,
>
> I have an array similar to this:
>
> tmp <- array(1:6, c(2,3,3))
> n1 <- c("one", "two")
> n2 <- c("three", "four", "five")
> n3 <- c("six", "seven", "eight")
> dimnames(tmp) <- list(n1, n2, n3)
> tmp[1,,1] <- NA
> tmp[1,3,2] <- NA
> tmp[2,,3] <- NA
> tmp
>
> How to subset !is.na(x) rows resulting
>
> , , six
>
> three four five
> two 2 4 6
>
> , , seven
>
> three four five
> one 1 3 NA
> two 2 4 6
>
> , , eight
>
> three four five
> one 1 3 5
>
> I have tried something like
>
> tmp[!apply(is.na(tmp), 1, all),,]
>
> with negative results.
>
> Thanks
> -Lauri
There might be an easier way, but here is one approach. The problem
that you will have is that you will not be returning an object with
"consistent dimensions". Thus, you will end up with a list, not an array.
> apply(tmp, 3,
function(i) i[apply(i, 1,
function(x) !all(is.na(x))), ,
drop = FALSE])
$six
three four five
two 2 4 6
$seven
three four five
one 1 3 NA
two 2 4 6
$eight
three four five
one 1 3 5
HTH,
Marc Schwartz
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
