Henrique Dallazuanna wrote:
> Try: sapply(paste("Data$x", 1:3, sep=""),
> function(x)eval(parse(text=x)))
>
> On 07/01/2008, Gregory Gentlemen <[EMAIL PROTECTED]> wrote:
>> Dear R users,
>>
>> I'd like to evaluate a vector of characters. For example, say I
>> have a data frame called Data including the field names x1, x2, x3,
>> and I'd like to a list out of paste("Data$x", 1:3, sep=""). How can
>> I get list to evaluate paste("Data$x", 1:3, sep="") as an R object
>> rather than a string?
>>
>> Thanks in advance for you assistance. Gregory
> fortune(106)
If the answer is parse() you should usually rethink the question.
-- Thomas Lumley
R-help (February 2005)
:-)
Try this:
> Data <- data.frame(x1 = 1:3, x2 = letters[1:3], x3 = 4:6, x4 = 8:10)
> Data
x1 x2 x3 x4
1 1 a 4 8
2 2 b 5 9
3 3 c 6 10
Since the only part that is varying is the column names:
Data[, paste("x", 1:3, sep="")]
x1 x2 x3
1 1 a 4
2 2 b 5
3 3 c 6
or
> subset(Data, select = paste("x", 1:3, sep=""))
x1 x2 x3
1 1 a 4
2 2 b 5
3 3 c 6
See ?subset. Alternatively, see ?get for other ways of returning R
objects using character vectors.
For example, a bit more convoluted, but you could also do:
MyDF <- "Data"
Cols <- paste("x", 1:3, sep="")
> get(MyDF)[, Cols]
x1 x2 x3
1 1 a 4
2 2 b 5
3 3 c 6
This gives you more flexibility in having both the name of the data
frame and the desired subset of columns within the data frame as
character vectors.
HTH,
Marc Schwartz
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