Hi Louis, If I am understanding your question correctly, here is one way: suppose your matrix is M of dimension n x k.
D <- data.frame(M) # convert to data frame ones <- rep(1, n) # a column of 1s Now you can count the number of repeats of each unique row. aggregate( ones, by = as.list(D), FUN = sum) The output will be a data frame with the unique rows, and a column at the end labeled "x" with the frequency of each unique row. Once you get this you can convert to a list, manipulate, etc. I am sure that there exist faster/better methods. Best, Jay On Dec 21, 2007 5:03 PM, Louis Martin <[EMAIL PROTECTED]> wrote: > Hi, > > I have a matrix of duplicate rows. How to output a list the unique rows with > their count? I have used "unique" to have the unique rows, but can't produce > the occurences of each unique row. > > Thanks > > Louis > > > > --------------------------------- > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- *************************************************** G. Jay Kerns, Ph.D. Assistant Professor / Statistics Coordinator Department of Mathematics & Statistics Youngstown State University Youngstown, OH 44555-0002 USA Office: 1035 Cushwa Hall Phone: (330) 941-3310 Office (voice mail) -3302 Department -3170 FAX E-mail: [EMAIL PROTECTED] http://www.cc.ysu.edu/~gjkerns/ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
