You can use a loop... If x,y and z are your vectors containing Nx,Ny and Nz numbers respectively, then for (Ix in 1:Nx) for (Iy in 1:Ny) for (Iz in 1:Nz) { Point <- c(x[Ix],y[Iy],z[Iz]) do whatever you need with Point }
A (probably better) compromise may be: a <- matrix(0,nrow = Ny*Nz, ncol = 3) for (i in 1:Nx) { a[,2:3] <- expand.grid(y,z) a[,1] <- x[i] do whatever you want with a } --- dxc13 <[EMAIL PROTECTED]> wrote: > > useR's. > > I am working with an algorithm in which I will need > to create combinations > of all the points I have in a matrix. When I have 2 > variables, I simply use > expand.grid() to do this. Sometimes I am faced with > 3 or more variables and > if I run expand.grid(), R cannot process it due to > the huge size. Is there > any efficient way to workaround this? > > Thanks, > Derek > -- > View this message in context: > http://www.nabble.com/alternate-storage-options-tp14438736p14438736.html > Sent from the R help mailing list archive at > Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.