Yes, try this:
> library(Ryacas)
Loading required package: XML
> x <- Sym("x")
> y <- Sym("y")
> z <- Sym("z")
> Solve((x^2+y^2+3*z^3)/(5*z^2*x^3)==0, x)
[1] "Starting Yacas!"
expression(list(x == root(-(4 * (y^2 + 3 * z^3)), 2)/2, x ==
-root(-(4 * (y^2 + 3 * z^3)), 2)/2))
On Nov 29, 2007 5:06 PM, Søren Højsgaard <[EMAIL PROTECTED]> wrote:
> The Ryacas package might be able to do it...
> Søren
>
> ________________________________
>
> Fra: [EMAIL PROTECTED] på vegne af francogrex
> Sendt: to 29-11-2007 22:00
> Til: r-help@r-project.org
> Emne: [R] How can R be used to solve algebra equations?
>
>
>
>
>
> suppose I have this equation:
> (x^2+y^2+3z^3)/(5*z^2*x^3)=0
>
> and I want to find x in relation to the other variables which actually is:
>
> x=sqrt(-3*z^3-y^2) or x=-sqrt(-3*z^3-y^2)
>
> Can R give me this expression solution? I know there is uniroot, but here I
> want the "expression" not the value, because I do not have values for y and
> z.
>
> Thanks
> --
> View this message in context:
> http://www.nabble.com/How-can-R-be-used-to-solve-algebra-equations--tf4899794.html#a14034422
> Sent from the R help mailing list archive at Nabble.com.
>
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