Try split:
> x <- matrix(letters[1:4], 2)
> x
[,1] [,2]
[1,] "a" "c"
[2,] "b" "d"
> split(x, row(x))
$`1`
[1] "a" "c"
$`2`
[1] "b" "d"
-Christos
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Søren Højsgaard
> Sent: Monday, November 12, 2007 8:08 PM
> To: [EMAIL PROTECTED]
> Subject: [R] The "reverse" of do.call("rbind",) on a list
>
> Dear List,
> I want to turn the matrix
> > xm
> [,1] [,2]
> [1,] "a" "b"
> [2,] "d" "e"
>
> into a list "by rows" as:
> [[1]]
> [1] "a" "b"
> [[2]]
> [1] "d" "e"
>
> A (bad?) way of doing this is as
> > unlist(apply(xm,1, list), recursive=F)
> [[1]]
> [1] "a" "b"
> [[2]]
> [1] "d" "e"
>
> - but there must be a more elegant way. Can anyone help on
> this? Thanks!
> Søren
>
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
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