Thank you all! But the problem is that quantile() returns "how many data" are greater than p percent, and not a value in the domain of the vector under scrutiny. For example, I have a vector
> x [1] "-0,39559" "1,1916" "0,23214" "1,656" "-0,3439" "-0,50568" [7] "0,52281" "0,96209" "0,0087242" "-0,030727" "1,0935" "0,35159" [13] "0,79229" "0,81791" "0,3186" "1,0165" "0,65567" "-0,56474" [19] "-0,34662" "0,70435" "-0,73285" "-0,60452" "-0,92526" "-0,296" [25] "0,51298" "0,38654" "0,32469" "-0,92555" "0,53023" "0,050059" [31] "1,09" "-0,35462" "0,37674" "1,1409" "0,072098" "1,4234" [37] "1,43" "0,68532" "0,078089" "0,61944" and, if I want to see the 10th percentile, in Matlab I go >> prctile(x, 10) ans = -0.4067 But in R: > quantile(x, probs=.1) 10% 51.5 I need to obtain -0.4067, do you see what I mean? Thanks a lot again!! Jose Luis Aznarte M. escribió: > Hi there! Still struggling to translate Matlab code into R's tsDyn package. > Here is my question: Is there in R an equivalent function to Matlab's > prctile()? To the moment I thought it was quantile(), but I just > realized I was wrong. The definition of the Matlab function: > > prctile > Percentiles of a sample > SyntaxY = prctile(X,p) > Description > Y = prctile(X,p) calculates a value that is greater than p percent of > the values in X. The values of p must lie in the interval [0 100]. For > instance, if p = 50 then Y is the median of X > > Thanks!! > > -- -- -- Jose Luis Aznarte M. http://decsai.ugr.es/~jlaznarte Department of Computer Science and Artificial Intelligence Universidad de Granada Tel. +34 - 958 - 24 04 67 GRANADA (Spain) Fax: +34 - 958 - 24 00 79 ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
