The problem is that the drop is only applied (or not) after the subsetting, so
what R does is:
- Getting the subset, which means a 1 x 1 matrix.
- Only then It either returns that as is (when drop=FALSE), or removes ALL
dimensions of extent 1, regardless of whether these are rows or columns (or
higher dimensions).
And it can't keep any names, because what name should be returned? The name
'row1' is just as valid as 'col1'.
I guess if we could design everything anew, a solution would be to be able to
specify something like a[1,,drop='row'], or a[1,,drop=1] to drop the rows but
keep columns, and get a vector being equal to 'row1' (which in this case just
has length-1, and names 'col1')
That not how it's designed, but you could use 'adrop()' from the 'abind'
package:
abind:: adrop(a[1,,drop=FALSE], drop=1) first subsets, then drops the
row-dimension, so gives what you're looking for.
Hope this solves your problem.
Best regards,
Emil Bode
On 21/11/2018, 17:58, "R-devel on behalf of Dmitriy Selivanov"
<r-devel-boun...@r-project.org on behalf of selivanov.dmit...@gmail.com> wrote:
Hi Rui. Thanks for answer, I'm aware of drop = FALSE option. Unfortunately
it doesn't resolve the issue - I'm expecting to get a vector, not a matrix .
ср, 21 нояб. 2018 г. в 20:54, Rui Barradas <ruipbarra...@sapo.pt>:
> Hello,
>
> Use drop = FALSE.
>
> a[1, , drop = FALSE]
> # col1
> #row1 1
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 16:51 de 21/11/2018, Dmitriy Selivanov escreveu:
> > Hello here. I'm struggling to understand R's subsetting behavior in
> couple
> > of edge cases - subsetting row in a single column matrix and subsetting
> > column in a single row matrix. I've read R's docs several times and
> haven't
> > found answer.
> >
> > Consider following example:
> >
> > a = matrix(1:2, nrow = 2, dimnames = list(c("row1", "row2"), c("col1")))
> > a[1, ]
> > # 1
> >
> > It returns *unnamed* vector `1` where I would expect named vector. In
> fact
> > it returns named vector when number of columns is > 1.
> > Same issue applicable to single row matrix. Is it a bug? looks very
> > counterintuitive.
> >
> >
>
--
Regards
Dmitriy Selivanov
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