Previously, I've posted queries about this, and thanks to postings and messages in response have recently had some success, to the extent that there is now a package called nlmrt on the R-forge project https://r-forge.r-project.org/R/?group_id=395 for solving nonlinear least squares problems that include small or zero residual problems via a Marquardt method using a call that mirrors the nls() function. nls() specifically warns against zero residual problems.
However, I would still like to be able to convert expressions with example vectors of parameters to functions that optim() and related functions can use. The code below gets "almost" there, but 1) Can the code be improved / cleaned up? 2) Can the eval() of the output of the Form2resfun be avoided? 3) Can the extraction of the parameter names be embedded in the function rather than put separately? Off-list responses are likely best at this stage, while the tedious details are sorted out. I will post a summary in a couple of weeks of the results. Collaborations re: this and the larger package welcome, as there is considerable testing and tuning to do, but preliminary experience is encouraging. John Nash # --------- code block ----------- rm(list=ls()) # clear workspace Form2resfun <- function(f, p ) { cat("In Form2resfun\n") xx <- all.vars(f) fp <- match(names(p), xx) # Problem in matching the names of params xx2 <- c(xx[fp], xx[-fp]) ff <- vector("list", length(xx2)) names(ff) <- xx2 sf<-as.character(f) if ((length(sf)!=3) && (sf[1]!="~")) stop("Bad model formula expression") lhs<-sf[2] # NOTE ORDER formula with ~ puts ~, lhs, rhs rhs<-sf[3] # And build the residual at the parameters resexp<-paste(rhs,"-",lhs, collapse=" ") fnexp<-paste("crossprod(",resexp,")", sep="") ff[[length(ff) + 1]] <- parse(text=fnexp) # want crossprod(resexp) myfn<-as.function(ff, parent.frame()) } # a test y<-c(5.308, 7.24, 9.638, 12.866, 17.069, 23.192, 31.443, 38.558, 50.156, 62.948, 75.995, 91.972) # for testing t<-1:length(y) # for testing f<- y ~ b1/(1+b2*exp(-1*b3*t)) p<-c(b1=1, b2=1, b3=1) b<-p npar<-length(b) for (i in 1:npar){ bbit<-paste(names(b)[[i]],"<-",b[[i]]) eval(parse(text=bbit)) } tfn<-Form2resfun(f, b) ans<-eval(tfn(t=t,y=y, b)) print(ans) # --------- end code block ----------- ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel