Full_Name: Jason Polak Version: R version 2.5.0 (2007-04-23) OS: Xubuntu 7.04 Submission from: (NULL) (137.122.144.35)
Dear R group, I have noticed a strange anomaly with the shapiro.test() function. Unfortunately I do not know how to calculate the shapiro test P values manually so I don't know if this is an actual bug. So, to produce the results, run the following code: pvalues = 0; for (i in 1:17) { j = 1:(i+3); pvalues[i]=shapiro.test(j)$p; } plot(pvalues); print(pvalues); Now I just made the graph to illustrate that the p-values are strictly decreasing. To me this makes intuitive sense: we are using the Shapiro test to test normality of (1,2,3,4),(1,2,3,4,5), and so on. So the p-value should decrease. These are the p-values: [1] 0.9718776 0.9671740 0.9605557 0.9492892 0.9331653 0.9135602 0.8923668 [8] 0.8698419 0.8757315 0.8371814 0.7964400 0.7545289 0.7123167 0.6704457 [15] 0.6294307 0.5896464 0.5513749 However, there is an increase in p-value when you go from (1,..,11) to (1,..,12). Is this just a quirk of the Shapiro test, or is there an error in the calculation algorithm? ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel