I am sorry, it was my program's bug. Yes, subset works! Yes, nls works correctly!
I didn't pay enough attention to NAs. NA threw off start value estimation in my program. So, I got different results when I filtered NAs beforehand and filtered by subset. I also confused because subset does not appear in the code of the nls function. Then, I reached a wrong conclusion. Thank you very much for your time. Tadashi Kadowaki 11 Oct 2006 11:55:56 +0200, Peter Dalgaard <[EMAIL PROTECTED]>: > [EMAIL PROTECTED] writes: > > > Full_Name: Tadashi Kadowaki > > Version: 2.4.0 > > OS: Redhat Linux 9 > > Submission from: (NULL) (58.12.166.67) > > > > > > Doesn't nls function support subset? It seems not to work. > > And, there are no information in the online help. > > Has it sunk into oblivion? > > Whatever gave you those ideas? > > Yes, nls supports subset. > Yes, it does seem to work. > Yes, it is documented in the online help. > No, it has not sunk into anything. > > > > nls(density ~ SSlogis(log(conc), Asym, xmid, scal), DNase, subset=Run==1) > Nonlinear regression model > model: density ~ SSlogis(log(conc), Asym, xmid, scal) > data: DNase > Asym xmid scal > 2.345180 1.483090 1.041455 > residual sum-of-squares: 0.004789569 > > > -- > O__ ---- Peter Dalgaard Øster Farimagsgade 5, Entr.B > c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K > (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 > ~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907 > ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel
