On 8/24/06, Mitch Skinner <[EMAIL PROTECTED]> wrote: > On Thu, 2006-08-24 at 08:57 -0400, Gabor Grothendieck wrote: > > If your Z in reality is not naturally numeric try representing it as a > > factor and using > > the numeric levels as your numbers and then put the level labels back on: > > > > m <- n <- 5 > > DF <- data.frame(X = gl(m*n, 1), Y = gl(m, n), Z = letters[1:25]) > > Zn <- as.numeric(DF$Z) > > system.time(w1 <- reshape(DF, timevar = "X", idvar = "Y", dir = "wide")) > > system.time({Zn <- as.numeric(DF$Z) > > w2 <- xtabs(Zn ~ Y + X, DF) > > w2[w2 > 0] <- levels(DF$Z)[w2] > > w2[w2 == 0] <- NA > > }) > > This is pretty slick, thanks. It looks like it works for me. For the > archives, this is how I got back to a data frame (as.data.frame(w2) > gives me a long version again): > > > m <- 4500 > > n <- 70 > > DF <- data.frame(X = gl(m, n), Y = 1:n, Z = letters[1:25]) > > system.time({Zn <- as.numeric(DF$Z) > + w2 <- xtabs(Zn ~ Y + X, DF) > + w2[w2 > 0] <- levels(DF$Z)[w2] > + w2[w2 == 0] <- NA > + WDF <- data.frame(Y=dimnames(w2)$Y) > + for (col in dimnames(w2)$X) { WDF[col]=w2[,col] } > + }) > [1] 131.888 1.240 135.945 0.000 0.000 > > dim(WDF) > [1] 70 4501 > > I'll have to look; maybe I can just use w2 as is. Next time I guess > I'll try R-help first. > > Thanks again, > Mitch >
Also try na.omit(as.data.frame(w2)) ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel