I moved this to R-devel because I am wondering why the base package does
not allow you to convert from numeric to Date. Could we not have
something like this?
as.Date.numeric <- function(x, epoch="1970-01-01", ...) {
if (!is.character(epoch) || length(epoch) != 1)
stop("invalid epoch")
as.Date(epoch, ...) + x
}
Martyn
On Tue, 2006-07-11 at 12:58 -0400, Gabor Grothendieck wrote:
> Try this:
>
> library(zoo)
> as.Date(11328)
>
> See the Help Desk article in R News 4/1 for more on dates.
>
>
> On 7/11/06, pierre clauss <[EMAIL PROTECTED]> wrote:
> > Hi everybody,
> > I need your precious help for, I think, a simple request, but I do not
> > manage to solve this.
> >
> > When I use a "table" function with dates in the rows, the rows are coerced
> > to number after the table function.
> >
> > So I need to transform the row names into date format. But I do not manage.
> >
> > Therefore, for an example, I manage to write this :
> >
> > datetest<-"06/01/2001"
> > datetest<-as.Date(datetest,"%d/%m/%Y")
> > datetest<-as.numeric(datetest)
> >
> > to get 11328.
> >
> > But I do not obtain the inverse tranformation :
> >
> > datetest<-as.Date(datetest,"%d/%m/%Y")
> >
> > How do we get this please ?
> >
> > Thanks a lot for your solution.
> > Pierre.
> >
> >
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