Try this:
e <- as.expression("A")
identical(parse(text = as.character(e)), e) # FALSE
On 5/2/06, Parlamis Franklin <[EMAIL PROTECTED]> wrote:
> if 'e' is a vector of mode 'expression', will the following always
> return TRUE:
>
> identical(e, parse(text = as.character(e))) ?
>
> > (e <- expression(x, y, z, 200*f%/%d, sin(e)))
> expression(x, y, z, 200 * f%/%d, sin(e))
> > identical(e, parse(text = as.character(e)))
> [1] TRUE
>
> i have been relying on this fact in some of my code, and would be
> appreciative of any counterexamples.
>
> franklin parlamis
>
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